Solve, |x + 1/3|=|x-3|
I don't think there is a solution for this, lol
If you graph both sides of the equation as separate functions on the same graph, they never intersect because they have the same slope.
i agree with ambius
Hmm okay, thank you. My book claims that the answer is 4/3 but I got no solution myself. Thank you
oh wait,
did yo try to square both side first?
No thats the problem as it was written, I do nothing to it.
\[x+\frac{ 1 }{ 3 }=-\left| x-3 \right|\] \[-x-\frac{1}{3}=\left|x-3\right|\] \[-x-\frac{1}{3}=x-3\] \[-2x=-\frac{8}{3}\] \[x=\frac{8}{6}\] \[x=\frac{4}{3}\]
That's called doing maths.
Dat it is, thank you good sir or madam.
then u get: \[x^2+\frac{2x}{3}+\frac{1}{9}=x^2-6x+9\]
that's lead to \(x=4/3\)
way to go! I just got schooled in absolutes, lol
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