Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

f(x)=5x^2 f(x+h)-f(x)/h

OpenStudy (anonymous):

f(x+h) means where you see the x you add h DO NOT FOCUS ON OTHER NUMBERS

OpenStudy (anonymous):

10x Should be the final answer.

OpenStudy (anonymous):

@Zelda theres no limit here

OpenStudy (anonymous):

5(x+h)^2 -f(5x^2) ??

OpenStudy (anonymous):

yes then divide by h

OpenStudy (anonymous):

5(x^2+2xh+h^2)= 5x^2+10xh+5h^2

OpenStudy (anonymous):

5x^2+10x+5h

OpenStudy (anonymous):

Hey april, is there the word lim as h-> 0 before f(x)?

OpenStudy (anonymous):

5x^2+10xh+5h^2-(5x^2+10x+5h)=

OpenStudy (anonymous):

the answer i have is 10x+5h

OpenStudy (anonymous):

yes but is there any thing like this \[\lim_{h \rightarrow 0}\] on the question

OpenStudy (anonymous):

no

OpenStudy (anonymous):

professor answer is 5(2x+h) i dont undestand why i would divide by 5

OpenStudy (zehanz):

It would be (very much) more clear if everyone wouldn't just write peaces of the problem, but the whole thing:\[\frac{ f(x+h)-f(x) }{ h }=\frac{ 5(x+h)^2-5x^2 }{ h }=\frac{ 5(x^2+2xh+h^2)-5x^2 }{ h }\]See? Just keep on writing the complete fraction, simpifying it along the way, until you're done:\[\frac{ 5x^2+10xh+5h^2-5x^2 }{ h }=\frac{ 10xh+5h^2 }{ h }=\frac{ 5h(2x+h) }{ h }=5(2x+h)\]So finally we've lost the fraction! Sooner or later the question of what will happen if h goes to 0 will be asked. Here you see immediately that leads to 10x.

OpenStudy (zehanz):

Of course, you could write the answer also as 10x + 5h

OpenStudy (anonymous):

THANK YOU!

OpenStudy (zehanz):

You're welcome!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!