Question

Find the limit as x approaches 0 for (t^2)/(〖1-cos〗^2 t)

Answer 1

I think it should be

\[\lim_{t \rightarrow 0} \frac{t^2}{(1 - \cos(?))^2 t}\]



but if its as above you can remove a common factor of t from the numerator and denominator.

Answer 2

its not that that one haha its
\[\frac{ t ^{2} }{ 1-\cos ^{2}t }\]

Answer 3

\[\huge \frac{t^2}{\sin^2t}=\frac{1}{(\sin^2t )\times \frac{1}{t^2}}=\frac{1}{\frac{\sin^2t}{t^2}}\]
\[\lim_{t \rightarrow 0} \frac{\sin t}{t}=0\]

Answer 4

the answer is suppose to be 1...

Answer 5

sry \[\frac{\sin t}{t}=1\]
\[\frac{1}{1^2}=1\] yes

Answer 6

oh i see it, thanks!