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Find the perimeter of the parallelogram ABCD with vertices A(-4,-5), B(2,-5), C(4,-2) and D(-2,-2).
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so, there may be a way to do it simpler than what I'm going to suggest, but the folling is the most intuitively easy way in my mind: basically, you just need to calculate the length of 4 line segments, then add them together. this can be done using Pythagorean's theorem to calculate the distance between points! : ) for example, if you wanted to determine the distance between points A and B, the equation is: \[|AB| = \sqrt{(Bx-Ax)^{2}+(By-Ay)^{2}}\] Do the same for BC, CD, and DA then add them together to get your parimeter!
Thank you!
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