Question

If the position of a particle on the x-axis at time t is -5t^2, then the average velocity of the particle for 0≤t≤3 is...

Answer 1

So, the good news is that the change in velocity over time is linear (meaning there is a constant acceleration). Because this is the case, you can add your initial velocity (at t=0) and your final velocity (at t=3) together, then divide by 2 to get the average velocity.

Answer 2

so:
\[\frac{v _{o} + v_{f}}{2}=v _{average}\]

is this a calculus problem? because all that's necessary to get v initial and v final is to find the derivative of your original equation, then sub in the values 0 and 3 respectively.

Answer 3

Thank you so much! Yes, it's calculus. I was sure my teacher taught some different way and completely forgot everything from my physics class last year.

Answer 4

np, lol