Question

Question: One drink contains 5% fruit juice and another contains 50% fruit juice. How many gallons of each type should be combined to make 5 gallons of a drink that contains 40% fruit juice?
PLEASE HELP ASAP. I WILL GIVE OUT MEDALS AND FAN YOU. (:

Answer 1

@zaynahf @CalebBeavers @JuanitaM

Answer 2

i so drew a blank...:)

Answer 3

I dont get it. Im so confused.

Answer 4

i think i got it.

Answer 5

Can you help me?

Answer 6

x of .50 juice
5-x of .05 juice
amount of juice in final is
.50x + .05(5-x)

this equals .40 of 10 = 4
so,
.50x + .05(5-x) = 4

now solve for x

Answer 7

oop ,, meant to be 5 not 10

Answer 8

What?........

Answer 9

.40 of 5 = 2
so .50x + .05(5-x) = 2

Answer 10

let me try to explain...

you have a total of 5 gallons of juice
part 50% juice (.50x) the other part 5% juice .05(5-x)

Answer 11

ok

Answer 12

now that solution must equal 40% juice...so that is why you have to multiple .40*5 =2

Answer 13

now set both sides to equal each other....
.50x +.25 - .05x = 2
.45x + .25 = 2
.45x = 2 - .25
.45x = 1.75
x = 3.9 (rounded)....do you get this?

Answer 14

Sorta....

Answer 15

check this website out....maybe reading their explanations may help you get it.
http://www.purplemath.com/modules/mixture2.htm

Answer 16

to finish, i would use x = 4
which tellls you that you will use 4 gal of 50% juice

thus leaving 6 gallons of 5% juice

Good luck...

Answer 17

Im gonna just write that and hope for the best.. lol thanks(:

Answer 18

LOL.... you will do fine, mixtures can get a little confusing...