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can someone help me with this problem "Im dealing with Trig identities, inverse functions, and equations> Multiply and Simplify (sin x +csc x) (sin^2 x +CSC^2 x - 1)
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I know the answer is \[\sin ^{3}x + \csc ^{3}x\]
but how do they arrive at this answer?
U havent learnred about miltiplying trig functions?
do i just multipy by each term?
before you begin, turn \(\csc^2(x)-1\) into \(\cot^2(x)\)
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what im more confused about is what happens to the -1
oh yes, ok i see that identity
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