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Mathematics 20 Online
OpenStudy (anonymous):

FTC and definite integrals?

OpenStudy (anonymous):

integral from (0 to 2) of the function (x^3/3 +2x) dx

OpenStudy (anonymous):

isn't the anti derivative x^2 + 2?

OpenStudy (anonymous):

@zepdrix

zepdrix (zepdrix):

No the `derivative` is x^2+2. I think you went in the wrong direction :)

OpenStudy (anonymous):

Ohh ok. so i need to take the derivative -_- lol

zepdrix (zepdrix):

You do? :o

zepdrix (zepdrix):

Do you know how to apply the `Power Rule` to integrals? :)

OpenStudy (anonymous):

well it says to evaluate using FTC. yea it's like when you subtract 1 from the exponent

OpenStudy (anonymous):

something like that hahaha

OpenStudy (anonymous):

i meant add lol

OpenStudy (anonymous):

and divide by the exponent

zepdrix (zepdrix):

`Power Rule for Derivatives`: ~Multiply by the power. ~Decrease the power by 1. `Power Rule for Integration`: ~Increase the power by 1. ~Divide by the power. Ok good, seems you understand already :)

OpenStudy (anonymous):

lol yea :) hopefully i don't mess that process up ahahaha

OpenStudy (anonymous):

x^4/4 +x^2?

zepdrix (zepdrix):

One tiny boo boo, you forgot about the 3 under the first term.

OpenStudy (anonymous):

for the x^3/3 part?

zepdrix (zepdrix):

ya

zepdrix (zepdrix):

you `gain` a 4 on the bottom, it doesn't change your 3 to a 4 silly!

OpenStudy (anonymous):

OOPS! x^4/4*3

OpenStudy (anonymous):

i got 16/3

zepdrix (zepdrix):

That's what I'm coming up with also, I think that's correct!

OpenStudy (anonymous):

thanksssssssssss!

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