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OpenStudy (anonymous):
integral from (0 to 2) of the function (x^3/3 +2x) dx
OpenStudy (anonymous):
isn't the anti derivative x^2 + 2?
OpenStudy (anonymous):
@zepdrix
zepdrix (zepdrix):
No the `derivative` is x^2+2.
I think you went in the wrong direction :)
OpenStudy (anonymous):
Ohh ok. so i need to take the derivative -_- lol
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zepdrix (zepdrix):
You do? :o
zepdrix (zepdrix):
Do you know how to apply the `Power Rule` to integrals? :)
OpenStudy (anonymous):
well it says to evaluate using FTC. yea it's like when you subtract 1 from the exponent
OpenStudy (anonymous):
something like that hahaha
OpenStudy (anonymous):
i meant add lol
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OpenStudy (anonymous):
and divide by the exponent
zepdrix (zepdrix):
`Power Rule for Derivatives`:
~Multiply by the power.
~Decrease the power by 1.
`Power Rule for Integration`:
~Increase the power by 1.
~Divide by the power.
Ok good, seems you understand already :)
OpenStudy (anonymous):
lol yea :) hopefully i don't mess that process up ahahaha
OpenStudy (anonymous):
x^4/4 +x^2?
zepdrix (zepdrix):
One tiny boo boo, you forgot about the 3 under the first term.
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OpenStudy (anonymous):
for the x^3/3 part?
zepdrix (zepdrix):
ya
zepdrix (zepdrix):
you `gain` a 4 on the bottom, it doesn't change your 3 to a 4 silly!
OpenStudy (anonymous):
OOPS! x^4/4*3
OpenStudy (anonymous):
i got 16/3
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zepdrix (zepdrix):
That's what I'm coming up with also, I think that's correct!