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Find the derivatives of the following function from the definition in terms of x, f(x) and f′(x). g(x) = f(x)^2
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by the chain rule \[g'(x)=2f(x)f'(x)\]
I can't use the chain rule yet on it
Then use the product rule: So \[g'(x)=f(x)f'(x)+f'(x)f(x)\]
can't do it that way either...my prof wants it done by the definition
Oh, okay then, what you do here is expand F(x)^2, okay? So, say f(x) = x+1 So, (x+1)^2 = x^2+2x+1 Then plug this into the limit definition, lim h-> 0 (f(x+h)-f(x))/h which will give your new g'(x)
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ok then how would I do it if it is\[g(x)= \sqrt[3]{f(x)}\]
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