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For positive constants A and B, the force, F, between two atoms in a molecule at a distance r apart is given by F = -\frac{A}{r^2} + \frac{B}{r^3}. How fast does force change as r increases? (Your answer may involve A, B, and r.) If at some time t the distance is changing at a rate k, at what rate is the force changing with time? (Your answer may involve A, B, r, and k.) So I got the first part which is (2A/r^3)-(3B/r^4) but I'm not sure how to add the k in
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\[F = -\frac{A}{r^2} + \frac{B}{r^3}\] \[\frac{dF}{dr} = \frac{2A}{r^3} -\frac{3B}{r^4}\] \[\frac{dr}{dt} = k\] \[\frac{dF}{dt} = ?\]
THANKS!!!
What's your answer?
dF/dr*dr/dt=dF/dt (2A/r^3-3B/r^4)*k
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