Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

derivative of integral

OpenStudy (anonymous):

\[\int\limits_{3}^{x^3}lntdt\]

OpenStudy (anonymous):

the derivative of the integral is the integrand but in this case the upper limit of integration is \(x^3\) so you need the chain rule

OpenStudy (anonymous):

replace \(t\) by \(x^3\) and then multiply by the derivative of \(x^3\) namely \(3x^2\)

OpenStudy (anonymous):

you get \[\ln(x^3)\times 3x^2\] via the chain rule

OpenStudy (anonymous):

Did anyone else get \[3x^2\ln (x^3)\] because thats what I got but the answer sheet says 9x^2lnx...

OpenStudy (anonymous):

oh ok im not the only one

OpenStudy (anonymous):

like having \[F(x)=\int\ln(t)dt\] where the derivative is \(\ln(x)\) and then asking what is the derivative of \(F(x^3)\) which by the chain rule is \(F'(x^3)\times 3x^2\)

OpenStudy (anonymous):

they used the fact that \[\ln(x^3)=3\ln(x)\]

OpenStudy (anonymous):

just showing off the knowledge of the properties of the log

OpenStudy (anonymous):

clear right? \[3x^2\ln(x^3)=9x^2\ln(x)\]

OpenStudy (anonymous):

ohhhh i get it know

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!