Question

Help solving this please!

Answer 1

so, \[(4x-3)^{3/2}\] is the same as \[(\sqrt{4x-3})^3\]
and \[8\] is the same as\[2^3\]
so, \[\sqrt{4x-3}=2\]
can you take it from here?

Answer 2

x=25/4 is this correct?

Answer 3

4x-3=2^2
4x-3=4
4x=7
x=7/4

Answer 4

when you bring a square root to the other side, it becomes a square, so square the 2 and take it from there

Answer 5

Thank you.

Answer 6

does what i wrote make sense to you?

Answer 7

right, anything to the power of a 1/2 is the same as square rooting it. 'index laws'

Answer 8

Yes I forgot to square the 2

Answer 9

@Chelsea04 Just a note: \[\huge x^{n\over m}=\sqrt[m]{x^n}\] rather than your\[\large (\sqrt[m]{x})^n\].
The answer x=7/4 is still correct though.

Answer 10

Yea, I'm aware, it's still the same thing