Question

A circle has its center at (-2, -3) and a radius of 3 units. What is the equation of the circle?

(x + 2)2 + (y + 3)2= 9

(x + 2)2 + (y - 3)2= 9

(x - 2)2 + (y - 3)2 = 3

(x + 2)2 + (y + 3)2 = 3

Answer 1

ok :)

Answer 2

why whats wrong @ryan123345 ?

Answer 3

Equation of a circle with center (h, k) and radius r is\[(x-h)^2+(y-k)^2=r^2\]

Answer 4

sorry i was just doing something ok not B or C

Answer 5

@irishchelsc So what is the equation if center (h, k) = (-2, -3) and your radius r = 3?

Answer 6

isn't it (x-h)2 + (y-k)2

Answer 7

h is the x coordinate and k is the y?

Answer 8

Yes :)

Answer 9

A

Answer 10

Yay! thank god!

Answer 11

that makes life so much easier :)

Answer 12

u didnt get my message?

Answer 13

If center (h, k) = (-2, -3) and radius r = 3, then substituting in the values provides:\[(x-(-2))^2+(y-(-3))^2=(3)^2\]Simplify to obtain:\[(x+2)^2+(y+3)^2=9\]

Answer 14

thank you!! so much @ryan123345 and @stamp