Question

will give medal & fan!!(:

Answer 1

@ryan123345 @satellite73

Answer 2

@Chelsea04

Answer 3

for the first one, the center isn't even in the fourth quadrant, so ignore that one

Answer 4

do you know how to check where each centre is?

Answer 5

for the second one, the center is \((5,-7)\) and the radius is \(\sqrt{16}=4\) so that one stays completely inside the 4th quadrant, because 4 is less than 5 and 7

Answer 6

can you check the other two?

Answer 7

do you know how to check?

Answer 8

No how do you? :) @Chelsea04

Answer 9

ok, the formula for circles is:
(x-h)^2+(x-k)^2=r^2

Answer 10

yup!

Answer 11

do you know what the center of the third one is?
use
\[(x-h)^2+(y-k)^2=r^2\] for a circle with center \((h,k)\) and radius \(r\)

Answer 12

(h,k) are the coordinates for your centre. r is the radius of your centre

Answer 13

ill help him lol...

Answer 14

so for the 3rd one it's -4 for h And 2 for k?

Answer 15

lol

Answer 16

sorry, the opposite signs, because when you take it out of the brackets, it changes sign

Answer 17

yeah! my bad @Chelsea04

Answer 18

so the coordinates for your centre is (4,-2)

Answer 19

yeah is that a 4th quad? yeah right? :)

Answer 20

yes, but the question asks for the circle to be completely in the 4th quad

Answer 21

oh and it's like only half! lol so I got B and D (:

Answer 22

so, now is where the radius comes into the question. so remember the equation used r^2, so you have to remember to square root that number :)

Answer 23

but yes, those would be your answers

Answer 24

do you understand?