Question

Find the first six terms of the sequence.

a1 = 4, an = an-1 + 8

OPTIONS ARE
0, 8, 16, 24, 32, 40

12, 20, 28, 36, 44, 52

4, 12, 20, 28, 36, 44

4, 8, 16, 24, 32, 40
PLEASE HELP
I GIVE MEDALS

Answer 1

just put n=2,3,4,5,6

Answer 2

@RadEn where

Answer 3

im here :)

Answer 4

have u got it ?

Answer 5

well, i'll give example ...
a_1 = 4 (known)
a_2 = a_(2-1) + 8 = a_1 + 8 = 4+8 = 12
a_3 = a_(3-1) + 8 = a_2 + 8 = 12+8 = 20
so on ....

Answer 6

eek

Answer 7

looks it is an arithmetic sequence with difference is 8
just add by 8 to the next number

Answer 8

28 36 44 ?

Answer 9

yep

Answer 10

@RadEn what about a1 = 6, an = 2 • an-1

Answer 11

do same idea, just put n=2 to get a_2
so, a_2 = 2a_(2-1) = 2a_1 = 2*6 = 12
and so on ...

Answer 12

looks like a geometri sequence with the ratio = 2

Answer 13

72

Answer 14

what do you keep multiplying ?

Answer 15

and for the last one does it start with 4,then 12 or is it starting with 12

Answer 16

just multiply by 2 to the next term, they are be
6,12,24,48,96,192,...

Answer 17

i mean to get the next term

Answer 18

so for the last one it was 4 , 12 ,20, 28...

Answer 19

6,12,24,48,96,192
the first six