Question

A ball is thrown in the air. the relationship between the time the ball is in the air in seconds(t) and the height of a ball in feet above the ground(h) is represented by h=-16t^2+46t+6.How many seconds will it take for the ball to hit the ground?

Answer 1

when it will hit ground h=0
solve
-16t^2+46t+6=0

Answer 2

I got multiple choices A) 1/8 B)3/8 C)3 D)6
just need the steps to understand

Answer 3

When it will hit the ground translates to the fact that your height will be 0 ft so that means h=0
so you want to solve for t in the equation h=-16t^2+46t+6 when h=0:

0=-16t^2+46t+6 do you know where to begin?

Answer 4

maybe we have to factor it?!

Answer 5

yes for a quadratic you can factor or use the quadratic equation

Answer 6

ok you need to solve
-16t^2+46t+6=0
take -2 common

-2(8t^2-23t-3)=0
break mid term to have factors .
-2(8t^2 -24t+t-3)=0
-2(8t(t-3)+1(t-3))=0
(8t+1)(t-3)=0

t=3
t=-1/8

Answer 7

ok thanks that really helped