Question

What is the first derivative of f(x)=2x^2+2x?

Answer 1

f'(x) = 4x+2

Answer 2

Can you walk me through the steps?

Answer 3

\[\text D(2x^2 + 2x) = \text D(2x^2) + \text D(2x) = 4x + 2\]

Answer 4

Thanks @ParthKohli

Can you show me the steps with f(x)=c, which is 0?

Answer 5

\[f(x) = c = cx^0\]Now the power rule.

Answer 6

Yea, that is what I was thinking. Thanks!

Answer 7

You're welcome!

Answer 8

@ParthKohli , sorry to bother, but can you show me once more how the 2x is just 2 and not 2x?

I use the forumla f(x+delta x)-f(x)/delta x

Answer 9

2(1)x^1-1
2x^0
2(1)
2

Answer 10

Thankss!