What is S5 for 1000 + 500 + 250 + ... ?
@stamp @PeterPan
This series is not like the series we had earlier, which was an arithmetic series... This is a new and more cunning type of series o.O
It is a pattern. What is the pattern? Think different.
I'm trying to figure that pattern out
@Kayy_Drizzyy Take your time.
@Kayy_Drizzyy Hint: It is geometric. If you do not know what geometric sequence is, please open your textbook to the index, find the "geometric sequences" page number, and read the section.
Idk what the patterm is
is it \(S_5\) or is it \[\sum_{n=0}^{\infty}1000\left(\frac{1}{2}\right)^n\]?
So my pattern is (1/2) ? right because i did 1000(1/2) and got my next answer which was 500
o.O @Kayy_Drizzyy Don't give up :) Look at the second term, divide it by the first. Look at the third term, divide it by the second. Notice a pattern? :)
Oh you have it :)
The problem seems to go down not you means 100(1/2)=500 500(1/2)=250 250(1/2)=125 125(1/2)=62.5
My answer problem are large numbers . How do i get that answer
@satellite73
add
add by (1/2) ?
This is what is known as a Geometric Series.... Each term is just the previous term, multiplied to a constant known as... ... the COMMON RATIO
\(S_5\) if i read it correctly means you have exactly 5 terms. Add up the first five numbers
i know that but what am i adding by to get my S5 term ?
Which as you pointed out, is 1/2 Luckily, a formula exists for getting the sum of the first n-terms of a geometric series :) \[\huge S_n = a\left( \frac{1-r^n}{1-r} \right)\] Where as is your first term and r is your... ... COMMON RATIO >:D
I'm confused now
Well, what's your common ratio r? It's (1/2) right?
yes r is 1/2 but where does the A(1-1/2n) come from to get my answer ?
a is the very first term, which happens to be 1000 :)
and n is the number of terms you're adding, which happens to be 5.
okay so break it down to me so i can solve i it and get my answer.
\[\huge S_n = a\left( \frac{1-r^n}{1-r} \right)\] You're taking the sum of the first 5 terms, so n=5
\[\huge S_5 = a\left( \frac{1-r^5}{1-r} \right)\] Your series starts at 1000, so a = 1000
\[\huge S_5 = 1000\left( \frac{1-r^5}{1-r} \right)\] And your common ratio is 1/2 = 0.5
\[\huge S_5 = 1000\left( \frac{1-\left(\frac{1}{2}\right)^5}{1-\frac{1}{2}} \right)\] Now do the number-crunching :P
okay hold on
I still didnt get my answer from using my calc.
Try harder :D
I got my answer
What is it?
1937.5
Awesome, you got it! Now, you could have gotten the same answer if you just keyed in 1000+500+250+125+62.5 :D
lol thank you
:)
I need more help in the future so stay online ill tag you in the problem i need help with, but thanks a lot.
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