Question

Choose the equation that could be used to find three consecutive integers whose sum is 36.

n + (n + 2) + (n + 4) = 36

n + (n + 1) + (n + 3) = 36

n + (n + 1) + (n + 2) = 36

n + (n − 1) + (n − 3) = 36

Answer 1

n+(n+1)+(n+2)=36 :o)

Answer 2

Thank you!

Answer 3

To solve it:

n+(n+1)+(n+2)=36
3n+3=36
3n=33
n=11

11+(11+1)+(11+2)=36
11+12+13=36
36=36

Does that make sense? :o)