Question

Evaluate lim h->0 (1/3+h - 1/3)/h

Answer 1

I got 1 but is it correct?

Answer 2

If it is,
\[\lim \limits_{h \to 0} \frac{\frac{1}{3}+h-\frac{1}{3}}{h}\]
yes the answer is 1

Answer 3

Okay thanks :)

Answer 4

wait hold no that not the equation :/ it is lim->0 1 over 3 + h then - 1/3 over h sorry

Answer 5

so would it be -1/9 then?

Answer 6

\[\lim \limits_{h \to 0} \frac{\frac{1}{3+h}-\frac{1}{3}}{h}=\lim \limits_{h \to 0} \frac{-h}{3(3+h)h}=\lim \limits_{h \to 0} \frac{-1}{3(3+h)}=\frac{-1}{9}\]
Yes you're correct

Answer 7

okay thanks :)