Question

x2-10x+24=0

Answer 1

you want to find 2 x's that
\[x_1*x_2=24\] and \[x_1+x_2=-10\]

Answer 2

x^2-10x+24=0
(x-12)(x+2)=0
x=12,-2

Answer 3

thankyou

Answer 4

yw

Answer 5

3x2+7x-20=0

Answer 6

Tomo, the only thing worse than giving them the answer ... is giving them the wrong one.

Answer 7

ok, my bad.

x^2-10x+24=0
(x-6)(x-4)=0
x=6,4

Answer 8

can u please help and look attachment because, I need help im failing

Answer 9

help please

Answer 10

...

Do you know how to factor or what factoring is?

Answer 11

no, have no idea,it been a while since i were in school

Answer 12

Okay, the goal of factoring is the take a polynomial and make it into parts that when multiplied results in the original polynomial.

Or:

\[(x_{1}+\alpha _{1})(x _{2}+\alpha _{2})=x _{1}x _{2}+\alpha _{1}x _{1}+\alpha _{2}x _{2}+\alpha _{1}\alpha _{2}\]

Or, referring to the first post:

What times what equals the number with no x's and which same two numbers when added equals the number with a single x.

Answer 13

x1+x2

Answer 14

Using a difference example say:

\[x ^{2}+7x+12=0\]

What we are asking for is what can be a1 and a2 (alpha sub 1 and 2).

Well, another way of asking is:

a * b = 12
a+b=7

The numbers that can be for a and b are those that satisfy both equations:

a*b=12
a=1 b=12
a=2 b=6
a=3 b=4

Because there are no negative numbers in this example, these are the only answers needed because a <-> b.

The second part asks us to add those two answers together:

a+b=7
For the first solution we found to the last part a+b = 13 (1+12=13)
That is incorrect.
Then: 2+6=8 =/=7
Finally: 3+4=7.

Therefore, a=3 and b=4

So:

(x+3)(x+4) gives us x^2 + 3x + 4x + 12 or x^2 +7x +12 which is what we wanted to acquire.

Try and see if you can get started on your problem(s).

Answer 15

ok

Answer 16

so if i had 10x2+x-3=0 the first solution would be a=5,b=7
A+b=7

Answer 17

can, i do lcd