Question

(7xy^3+5x^3y^4)-(4xy^3-2x^3y^4)

Subtract the polynomials.

Answer 1

first you find like terms in the first and second sets of parenthesis
and use those to do simple subtraction

Answer 2

Do you know the Distributive Property? @reason

(7xy^3+5x^3y^4)-(4xy^3-2x^3y^4)=

7xy^3 + 5x^3y^4) -1* (4xy^3-2x^3y^4)=

Answer 3

I know you have to change the sign to plus and the second part becomes plus -4xy^3+2x....etc

Answer 4

( 7xy^3 + 5x^3y^4) -1* ( 4xy^3 -2x^3y^4 )=

( 7xy^3 + 5x^3y^4) + (-1)*( 4xy^3 ) + (-1) (-2x^3y^4) =

So the negative one is distributed over the two terms in the second expression.


( 7xy^3 + 5x^3y^4) + (-1)*( 4xy^3 ) + (-1) (-2x^3y^4) =

7xy^3 + 5x^3y^4 - 4xy^3 + ____?_____ What goes here? @reason

Answer 5

@ reason Look at just this part:

(-1) (-2x^3y^4) --> What is negative one times negative 2 x cubed y to the fourth?

Answer 6

i'm having trouble with this one

Answer 7

=(

Answer 8

(-1) (-2x^3y^4) = 2x^3y^4

Answer 9

( 7xy^3 + 5x^3y^4) + (-1)*( 4xy^3 ) + (-1) (-2x^3y^4) =

7 xy^3 + 5 x^3y^4 - 4 xy^3 + 2 x^3y^4 =

3 x y^3 + 7 x^3 y -->@reason