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OpenStudy (anonymous):

if a rock is thrown upward with an initial velocity of 64ft per second from the top of a 25-foot building write the height(s) equation using this information, how high is the rock after1 second after how many seconds will rock reach max

OpenStudy (anonymous):

OpenStudy (anonymous):

can u please help

OpenStudy (jtvatsim):

what's the attachment for?

OpenStudy (anonymous):

theres graph on there i dont understand

OpenStudy (jtvatsim):

ok, i'll look at your first question for now...

OpenStudy (anonymous):

also okay thankyou

OpenStudy (jtvatsim):

Alright, the way I learned it the height equation is: h(t) = v*t -4.9t^2 Do you have a different version? Just want to use what's familiar to you.

OpenStudy (jtvatsim):

Actually, you might have h(t) = v*t - 16t^2 since you're using ft/sec

OpenStudy (jtvatsim):

Let me know if you have a different formula cuz that will change the answer

OpenStudy (anonymous):

no thats it of 64ft per second from the top of a 25

OpenStudy (jtvatsim):

ok, so we start from a height of 25 ft. That means we must adjust the equation to become: h(t) = v*t - 16t^2 + 25 That + 25 will ensure that at t = 0, h(t) = 25 like we want.

OpenStudy (jtvatsim):

Now you know what v is, since that is just the speed that you throw it at initially. In other words, v = 64 ft/sec.

OpenStudy (jtvatsim):

Thus, we have: h(t) = 64t - 16t^2 + 25 or to make it look nicer algebraically.. h(t) = -16t^2 + 64t + 25

OpenStudy (jtvatsim):

Now, do you think you can find what the height is after 1 second?

OpenStudy (anonymous):

yes im just adding1 to equation right

OpenStudy (jtvatsim):

yes, if you mean you are plugging in t = 1. So, make all the t's into 1's. :)

OpenStudy (jtvatsim):

t is just the time

OpenStudy (anonymous):

ok then i substitute16 right

OpenStudy (jtvatsim):

Well, you should get this: h(1) means the height at 1 second, so: h(1) = -16(1)^2 + 64(1) + 25

OpenStudy (jtvatsim):

solve the right side and what do you get?

OpenStudy (anonymous):

-48

OpenStudy (jtvatsim):

ok, that's not quite it, what calculations did you do?

OpenStudy (anonymous):

16^2

OpenStudy (jtvatsim):

ok, the ^2 only affects the 1

OpenStudy (jtvatsim):

the equation is -16t^2 not -(16t)^2, which is a big difference. the exponent only effects the time

OpenStudy (jtvatsim):

so, it's easier than what you thought cuz it's just 1^2 which is 1

OpenStudy (jtvatsim):

so -16(1)^2 = -16. if you use that what does your answer become?

OpenStudy (anonymous):

0

OpenStudy (anonymous):

if i divide 16/16right

OpenStudy (jtvatsim):

oh.. you don't have to divide by 16

OpenStudy (anonymous):

okay

OpenStudy (jtvatsim):

it's just straight up addition of -16(1)^2 + 64(1) + 25

OpenStudy (jtvatsim):

so that's just -16 + 64 + 25

OpenStudy (jtvatsim):

or 73, does that make sense? :)

OpenStudy (anonymous):

ok

OpenStudy (jtvatsim):

So the height after 1 second is 73 feet. And we got that by plugging in t = 1 into h(t) = -16t^2 + 64t + 25.

OpenStudy (anonymous):

ok, how would i solve for the graph

OpenStudy (jtvatsim):

are you referring to the one about Bob's salary?

OpenStudy (anonymous):

yes

OpenStudy (jtvatsim):

ok, so the horizontal line is always your x, and the vertical line is always your y.

OpenStudy (anonymous):

ok, so would it be 2,4,6,8=230,000or270000 because it seem like its go by2

OpenStudy (jtvatsim):

are you doing part a) or which part are you on?

OpenStudy (anonymous):

parta

OpenStudy (anonymous):

of the graph it's confusing

OpenStudy (jtvatsim):

ok, so we just need to pick two coordinates. Let's do the first one. Here's one answer (0, 41000) because when x = 0 on the horizontal line, the graph is at 41000 on the vertical line.

OpenStudy (jtvatsim):

I'm reading between the lines to get the 41000 number, it's between 40000 and 42000.

OpenStudy (jtvatsim):

So how about at x = 2 on the horizontal line, where is the graph vertically at that point?

OpenStudy (anonymous):

46000

OpenStudy (jtvatsim):

exactly! So we write (2, 46000).

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

for linear equation how would i write that, try to take tutoring but my headphones are broken and is lost

OpenStudy (jtvatsim):

Alright, so I'm assuming you already found the slope right? Because you can't write a linear equation without the slope.

OpenStudy (anonymous):

no

OpenStudy (jtvatsim):

OK, so we'll start there first :)

OpenStudy (anonymous):

okay

OpenStudy (jtvatsim):

So, do you remember or have the definition of slope?

OpenStudy (anonymous):

in up right addneg down

OpenStudy (anonymous):

x=0

OpenStudy (jtvatsim):

ok, good. so we go up from 41000 to 46000 on the graph and go over from 0 to 2.

OpenStudy (jtvatsim):

Slope = rise / run or you can think of it as Slope = (up down) / (left right)

OpenStudy (jtvatsim):

So our slope is 5000 up / 2 right which is 5000/2 = 2500.

OpenStudy (jtvatsim):

that's it for slope

OpenStudy (anonymous):

ok

OpenStudy (jtvatsim):

Now to write a linear equation, it will look like this formula: y = m*x + b m is the slope, b is the y-intercept (the value of y when x = 0). When writing a linear equation you just leave x and y alone in the formula.

OpenStudy (jtvatsim):

We already know that m = 2500 and we know that y is 41000 when x = 0, so the b = 41000.

OpenStudy (jtvatsim):

Then, our linear equation is y = 2500x + 41000.

OpenStudy (jtvatsim):

and we are done.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can u look at the next one then thats it

OpenStudy (jtvatsim):

sure

OpenStudy (jtvatsim):

At the beginning of the question they told us that x = 0 was 2002.

OpenStudy (jtvatsim):

so what would x = ? in 2008

OpenStudy (anonymous):

23000or0

OpenStudy (jtvatsim):

that might be the salary, but that's the vertical line. Horizontally, we have x = 0 is 2002, x = 1 is 2003, x = 2is 2004... so x = 6 is 2008 right?

OpenStudy (anonymous):

yes

OpenStudy (jtvatsim):

so his salary is given by y = 2500x + 41000, which is what we did all the hard work for earlier.

OpenStudy (jtvatsim):

To figure out what his salary will be in 2008 then, we just plug in x = 6

OpenStudy (anonymous):

i wasnt sure ok

OpenStudy (anonymous):

ok

OpenStudy (jtvatsim):

so that is y = 2500(6) + 41000

OpenStudy (jtvatsim):

and that is 56,000

OpenStudy (anonymous):

so,that's how i would do the steps thanku

OpenStudy (jtvatsim):

yep, no problem

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