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Mathematics 7 Online
OpenStudy (anonymous):

help me plz on this question

OpenStudy (anonymous):

|dw:1360374989896:dw|

OpenStudy (anonymous):

A)9 B)8 C)7 D)6

OpenStudy (anonymous):

Well, we'll do this using perfect squares. We know that: \[\sqrt{36} = 6\ \& \ \sqrt{64} = 8 \] So since 56 is between these two numbers, but closer to 64 than it is to 56, it is probably closer to 8 than 6, so most likely it is about 7. You can confirm by checking: \[\sqrt{56} \approx 7.48\] So, it is closer to 7, as .48 rounds down. So our initial guess was right.

OpenStudy (anonymous):

square each of those numbers. the closest to 56 is your answer

OpenStudy (anonymous):

the answers r 9 8 7 6

OpenStudy (anonymous):

ther is no 56

OpenStudy (anonymous):

I never said 56, I said we were approximating using the perfect squares, read my paragraph again.

OpenStudy (anonymous):

no tomo said 56

OpenStudy (anonymous):

9^2 =81 8^2=64 7^2 = 49 6^2 = 36 |81-56| = 25 |64-56| = 8 |49-56| = 7 |36-56| = 20 as zelda was saying, 7 is the number you should choose, since its square is closest to 56

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