Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

I had to drop a ball from 15ft, and i recorded the height of each bounce. 15ft 13ft 11ft 9ft 7ft How do i use the geometric series formula to find the total distance of the height the ball has traveled?

OpenStudy (anonymous):

The sum of a geometric series for |r| < 1 is given by \[\sum_{n=0}^{\infty}a _{1}*r ^{n} = \frac{ a _{1} }{ 1-r }\]

OpenStudy (anonymous):

how do i know what the r^n and the a_1 represent?

OpenStudy (anonymous):

Are you sure this is a geometric series? It has to differ by something constant: For example if your first term was 16 and r = 1/2, then your series would be 16 + 8 + 4 + 2 + 1 + 1/2 +... Here your terms differ by a difference of 2. That's not geometric.

OpenStudy (anonymous):

@what do i do then? bc thats what im being asked

OpenStudy (anonymous):

@khoala4pham

OpenStudy (anonymous):

is there a way to turn this into a geometric series?

OpenStudy (anonymous):

I don't think so. A geometric series must have each next term multiplied by some fractional constant (if it converges)

OpenStudy (anonymous):

how can i switch up the numbers a little to make it work?

OpenStudy (anonymous):

@khoala4pham

OpenStudy (anonymous):

I don't know honestly. It's an arithmetic sequence not a geometric. As of yet, I can't think of any transformations that will make it converge.

OpenStudy (anonymous):

can you come up with a completely different heights to make it work? i just made these up. i didnt have to drop it from 15 ft

OpenStudy (anonymous):

Are you positive these are the numbers? The way I see it is that if you continue the pattern, it will be 9ft, 7ft, 5ft, 3ft, 1ft...what's next. Physically the ball bounces "infinitely" many times but it will converge. The ball bounces in the path of a geometric series yet this is arithetic.

OpenStudy (anonymous):

Wait, you made these numbers up? So what are the real numbers?

OpenStudy (anonymous):

i was supposed to come up with numbers.i wasnt given any numbers

OpenStudy (anonymous):

OH. Okay. Let's just make up some numbers then! That sounds fun. xD So let's say you started with a height of 16 and after each bounce, the ball bounces only 3/4 the height of the previous: 16, 12, 9...etc... if you look at the formula above, you see that a1 is 16 and r = 3/4. Thus the sum that the ball travels is 16/(1-3/4) = 16/(0.25) = 64. Now that is an impressive number.

OpenStudy (anonymous):

wait, so after 9 its 7? and after that its 6? howd you get 3/4?

OpenStudy (anonymous):

i need 5 heights, i dont get this

OpenStudy (anonymous):

No, I'm making up an entirely new series. A geeomtric series differs in each of its terms by a constant. For example, if I decided that each term would be half the previous starting with 32, my series would be 32 + 16 + 8 + 4 + 2 + 1 + 1/2 + 1/4 +... And this pattern continues indefinitely. However, the sum, the infinite sum, DOES exist. Its value is 64. Because a1 = 32 and r = 1/2. Thus S = a1/(1-r) = 32/ (0.5) = 64.

OpenStudy (anonymous):

In my problem above, I set that each next one will be 3/4 the height of the previous, starting with 16: so our series is 16 + 12 + 9 + 27/4 + 81/16 +... Do not be alerted by the sudden increase in the numbers such as 27 and 81--they are actually really small values.

OpenStudy (anonymous):

how would i come up with 2 other different series that also start off with a height of 16?

OpenStudy (anonymous):

Change the rate at which it falls. For example, another serie could be that the original height is 16 but the ball only bounces back 1/2 the previous height. Then you could try when the ball is really bad and bounces back 1/4 the previous height. (I'm choosing these numbers because they are really easy to multiply and divide with 16.

OpenStudy (anonymous):

oh, i get it. thanks sooo much. i´ve been trying to get help on this assignment for days now

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!