Verify identity cot(θ)+tan(θ)=csc(θ)sec(θ) Any hints how to start? I'm completely stuck on this one... Thanks.
Last Resort: Change everything to sine and cosine.
ok let me see
ok so i got (cos(θ)+sin(θ))/(cos(θ)+sin(θ))=(1)/(cos(θ)sin(θ))
stuck again
left side will be 1
what do i do with right side?
the addition of fraction is not right. \[\frac{a}{b} + \frac{b}{a} \color{red}\neq \frac{a+b}{b+a}\]
you right... ok, let me redo it, thx
ok, so when i did multiply it as it should be I got (1)/(cos(θ)sin(θ)) on both sides. is that correct?
\[\frac{ \cos \theta }{ \sin \theta } + \frac{ \sin \theta }{ \cos \theta } \] then multiply by the common factors so first fraction by cos theta and the second by sin theta so you get : \[\frac{ \cos^2 \theta + \sin^2 \theta }{ \sin \theta \cos \theta}\] according to the pythagorean the numenator will equal 1 so you get 1/ sin theta cos theta
thats what i got, perfect thx
on the other side csc theta sec theta can be simplified to: (1/sin theta ) (1/cos theta) so you get 1 / sin theta cos theta QED
QED and the trigie biggie
EXACTLY
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