What are the values of a & b ?

Question

anonymous · Answer

attachment

anonymous · Answer

i got this answer is it correct ?

anonymous · Answer

Are you in pre calc?

anonymous · Answer

no geometry

anonymous · Answer

Are you using sine and cosine?

anonymous · Answer

no .....

anonymous · Answer

Okai I only know how to figure it out with that...sorry ._.

anonymous · Answer

its ok

geerky42 · Answer

$$\dfrac{21}{20} = \dfrac{29}{b} = \dfrac{20}{a}$$

geerky42 · Answer

$$\dfrac{21}{20} = \dfrac{29}{b}$$$$\dfrac{21}{20} = \dfrac{20}{a}$$

directrix · Answer

@HolyRoller.
The value of b doesn't satisfy the converse of the Pythagorean Theorem.

20^2 +(400/21)^2 = (20/21)^2  FALSE
So, I'm thinking b is not 20/21. 

For b, the lengths of the corresponding sides of the similar triangles is:

20/21 = b/29 which cranks out a value of b not equal to 20/21.

I did get the same value of a that you attached using a/20 = 20/21.

whpalmer4 · Answer

Yeah, I get the same value of a, and b is as suggested by @geerky42 and @Directrix, and if you plug a, b, and the known side (20) in to the Pythagorean it all fits.

anonymous · Answer

so was my answer correct?? @whpalmer4

whpalmer4 · Answer

As previously mentioned, one is, one is not.