Question

The amount of heat released when 150 grams of ice at 0 degrees Celsius is converted into liquid water at 0 degrees Celsius is ____ J.

Answer 1

To convert 1 g of ice at 0 ºC to 1 g of water at 0 ºC, 334 J of heat must be absorbed by the water.

150 grams times 334 J per gram = ? J
@jmays14

Answer 2

You may want to do some reading at this link:
http://www.kentchemistry.com/links/Energy/HeatFusion.htm

Answer 3

"Amount of heat released" doesn't sound right... the ice absorbs heat when changing phase to liquid.

Answer 4

@Directrix so it will be 50,100

Answer 5

That's what I think from the reading I did. Now, I can't say that I am certain that I interpreted what I read correctly but it made sense to me. :) 50,100

Answer 6

Okay what about this problem
____ J of heat is required to raise the temperature of 100. grams of water by 10. degrees Celsius

Answer 7

@Directrix

Answer 8

I don't know this out of my head. I'll have to read at that link above.

Answer 9

okay i got 10 but idk if thats correct

Answer 10

Did you see the image attached below at the site: http://www.engineeringtoolbox.com/heat-units-d_664.html

Answer 11

yes i see it but that still doesnt help me figure out the answer all its telling me is the definition

Answer 12

So, 4.184 J for 1 degree increase for 1 gram.

For 1 gram to move 1 degree requires 4.184 J.

100 grams require 4.184 J times 10 (degrees up) times 100 (number of grams)=?

What is the product of 4.184 * 10* 100. I think but am not certain that that's the number of needed Js.

Answer 13

4,184

Answer 14

4,184 Joules is the product of the numbers.