Question

Given sinӨ = 6/11 and sec Ө > 0, find cosӨ and tanӨ

Answer 1

What have you tried to do so far?

Answer 2

I just don't know what to do at all >_<

Answer 3

OK, so you might want to think of using the trig identity which says:

sin^2(x) + cos^2(x) = 1

Answer 4

If you plug in your value of sin(x) = 6/11, you can solve for cos(x).

Answer 5

Those are the answer options

Answer 6

ok... start by drawing a right triangle



find a by using pythagoras' theorem..

then since sec > 0

then cos is.., and since sin > 0 then its a 1st quadrant angle...

Answer 7

you can now find cos and tan

Answer 8

So I can't use sine and cosine to find a? I have to use Pythagoras theorem?

Answer 9

if you find a by pythagoras

then if

\[\sin(x) = \frac{6}{11}\]

then

\[\cos(x) = \frac{a}{11} ... and... \tan(x) = \frac{6}{a}\]

Answer 10

Oh I get you

Answer 11

its the simplest way to do these questions..

draw the triangle find the missing side

check the quadrant

find the other ratios...

Answer 12

So my a would be square root of 85 or 9.22

Answer 13

use sqrt 85 since that is one of your answer choices... don't use the decimal.

the sqrt 85 will give you an exact value, rather than a decimal approximation.

Answer 14

So my answer would be a sqrt 85/11 c:

Answer 15

yes that will be cos

and tan will be

\[\tan(x) = \frac{6}{\sqrt{85}}\]

Answer 16

ohhh okai I see c:

Answer 17

Thank you n.n

Answer 18

so to me cos looks like the 1st option you posted.... not sure of the letter...

Answer 19

yeah the first one is a cx

Answer 20

ps... I used x instead of theta... sorry about that

Answer 21

it's okai I picked up on that cx