9sqrt6 then round three decimals
got 531441 have 20 problems need help with6
\(\large 9\sqrt6 \) is already in simplest terms... now use a calculator to round the value to 3 decimal places.
got531441 if round530441
those are huge numbers.... the number you should be getting should be less than 25... is this the correct expression: \(\large 9\sqrt6 \) ???
yes
9sqrt6~~
ok... sqrt6 is about 2.499 so 9 times 2.449 = ????
22.041
somewhere there....
i think they wanted the approximation accurate to 3 decimal places so let your calculator calculate \(\large 9 \times \sqrt6 =\) ???? then round this to 3 decimal places... if you do it this way, you answer would be 22.045
ok, iam going to calculate
ok, so if round three decimals it would be22.046
hmm.. when i let my calculator do it, it gives 22.045407.... so 3 decimal places give 22.045...
217.474
thats what, i got the same as u but it said it were wrong and it's217.474
where did i say it is 217.474 ???
in mathlab,i know i got the same as you dont know what i am doing wrong because i am using google calculator online
now i have have to solve9sqrt2
lol... i used google also...
i know, i had got the same as u but when i put it end it said it was wrong no offense to uwww.aiunivmathlab.com
its my hwassignment and every answer i put in it's saying it's wrong, i only got one problem right
oh wow is iam doing something wrong
the url does not work.... is it correct? anyway, all the these are calculator prolbems. they want a decimal approximation for the values of the the expressions.... the only way to get it wrong is if you enter the incorrect number of decimal places, or you entered the problem incorrectly...
is this url correct: www.aiunivmathlab.com ????
that should work iam on unit5homework
sorry... i'm getting the login screen...
okay
is this the type of problems on the homework? i don't see how the answer we came up with is incorrect... it is a calculator problem... it could be a problem on their end
yes, probably
can we try to do, to go over it together the 24574955 pwaiu.123
i can help you with a problem but i don't know what "24574955 pwaiu.123" is
okay 9^2~~
is that "9 squared" or \(\large 9^2 \) ???
9^
says sqrt of 9^2
the carat symbol "^" is used to refer to exponentiation... so 9^2 means \(\large 9^2 \)
okay
1458
ok... so you want "the square root of (9^2) or \(\large \sqrt{9^2} =\) ??? is this correct?
is the previous post the correct problem?
81
yes, but they gave me another one because it were wrong.
81 is incorrect...
\(\large \sqrt{9^2}=\sqrt{81}=9 \)
no it this9sqrt2
but it asking me to round 3places
\(\large 9\sqrt2 \approx 12.7279220614 \) if you were to approximate this to 3 decimal places, what should it be?
12.727911
3 decimal places means 3 digits (numbers) after the decimal..... so you should have 12.728 you need to look at the 4th digit after the decimal (that would be the "9").. if that digit is 5 or bigger, then add 1 to the third digit. if that digit is less than 5, then the you can disregard all the digits past the third digit
12.728922
no... "three decimal digits" means you only have 3 digits to the right of the decimal... so your answer should be 12.728
okay
how did you get ~~ on cal
3sqrt8~~
i got8.4852814
round would be8.4952814
no... 8.48528137424 rounded to 3 decimal places would be 8.485
okay
it's still ssaying it's wrong
it,s not going to let me copy and paste
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