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Mathematics 16 Online
OpenStudy (anonymous):

Any help is appreciated :) equations Q=mcΔT and Q=ml pic attached

OpenStudy (anonymous):

OpenStudy (anonymous):

Like i know the equations \[Q=mc \Delta T \] and \[Q=ml \] but idk how to find what goes where

OpenStudy (anonymous):

For # 10 so far I got m=143g

OpenStudy (anonymous):

You have everything you need m = mass c is a constant and deltaT is the change in temp.

OpenStudy (anonymous):

Q is the heat solve for Q

OpenStudy (anonymous):

oh ok cool that helps! :)

OpenStudy (anonymous):

c is not 20 and deltaT is not 45

OpenStudy (anonymous):

ohhh :(

OpenStudy (anonymous):

c is the specific heat for water do you know what that is?

OpenStudy (anonymous):

no :/

OpenStudy (anonymous):

c = 4.184 J/gC

OpenStudy (anonymous):

deltaT is the change in temp so final - initial

OpenStudy (kyosuke):

calor específico del agua es cantidad de calor que hay que suministrar a la unidad de masa de una sustancia para elevar su temperatura en un grado , en el agua el calor especifico es aproximadamente 1 cal/g°C

OpenStudy (anonymous):

so m=143 c=4.184 Δt=25

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

so q= 14,957.8

OpenStudy (anonymous):

q is in joules

OpenStudy (anonymous):

oh lol 14,957.8 joules

OpenStudy (anonymous):

Thank u! :)

OpenStudy (anonymous):

your welcome

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