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Solve for x 37=5(1.02)^x
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Okay, do you understand how to use logarithms?
yes
okay, firstly you want to simplify, so divide 5 from both sides
ok
\[\frac{37}{5}=1.02^{x}\]
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yup did that and I got 7.4=1.02^x
Now take the natural logarithm of both sides, so that you have \[\ln(\frac{37}{5})=x * \ln(1.02)\]
ok
so then x=1.982
Is that correct
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no
You want to do \[x=\frac{\ln(\frac{37}{5})}{\ln(1.02)}\]
yes
Did you do it?
yes I got 101.071 is that correct
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try it out
yup thats it thank you
No problem. :)
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