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OpenStudy (anonymous):
okay, this one is easy
OpenStudy (anonymous):
ok where do I begin
OpenStudy (anonymous):
Firstly, divide both sides by 0.4 so that we can cancel it out
OpenStudy (anonymous):
ok \[\frac{ 67 }{ 0.4}\]=e^5x
OpenStudy (anonymous):
Do you know what you get if you take the natural logarithm of e?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
Try it in your calculator
OpenStudy (anonymous):
I got 1
OpenStudy (anonymous):
\[\ln(\frac{67}{0.4})=5x*\ln(e)\]
OpenStudy (anonymous):
perfect, so we know that ln(e)=1, do you see how to solve the rest of the problem?
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OpenStudy (anonymous):
I think so hold on a minute and let me do it
OpenStudy (anonymous):
so is the answer 1.024
OpenStudy (anonymous):
It's easy to check, just plug it right back into the equation
OpenStudy (anonymous):
yup ok thanks
OpenStudy (anonymous):
Did you have any more logarithm questions? also, any question involving something like 0.4e, if you can divide out the coefficient, you will always know that ln(e)=1, which makes the rest a lot easier for you.
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OpenStudy (anonymous):
I do it is Solve for x again [4e ^{x}+e ^{x}(4x-3)=0\]