Solve for x 67=0.4e^5x
okay, this one is easy
ok where do I begin
Firstly, divide both sides by 0.4 so that we can cancel it out
ok \[\frac{ 67 }{ 0.4}\]=e^5x
Do you know what you get if you take the natural logarithm of e?
no
Try it in your calculator
I got 1
\[\ln(\frac{67}{0.4})=5x*\ln(e)\]
perfect, so we know that ln(e)=1, do you see how to solve the rest of the problem?
I think so hold on a minute and let me do it
so is the answer 1.024
It's easy to check, just plug it right back into the equation
yup ok thanks
Did you have any more logarithm questions? also, any question involving something like 0.4e, if you can divide out the coefficient, you will always know that ln(e)=1, which makes the rest a lot easier for you.
I do it is Solve for x again [4e ^{x}+e ^{x}(4x-3)=0\]
I'm not sure how that's formatted
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