please help solve using quadratic equation
x^2-3x-7=0

Question

please help solve using quadratic equation
x^2-3x-7=0

anonymous · Answer

use quadratic equatio formula

anonymous · Answer

i do not understand or know it

anonymous · Answer

Just for reference it is: $$x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

anonymous · Answer

i do not know how to do it

anonymous · Answer

Put it in the formula?

anonymous · Answer

Here gave you what a,b and c are. Just plug them in.

anonymous · Answer

how do i do the formula after i plug it in?

anonymous · Answer

@Hero, you take it from here...

anonymous · Answer

can someone give me a hint on what part to do first. when i said i dont know how to do it i ment i REALLY dont :(

anonymous · Answer

What they all told you earlier is true but maybe an explanation of what you are doing may help. When you are using the quadratic equation you are solving for an x value that will make $$x^2-3x-7$$ equal zero. Something that wasn't stated earlier either was how a,b, and c are actually found for the quadratic formula. $$ax^2+bx+c=0$$. Does this help at all?

anonymous · Answer

thank you this has just been a challenge for me i am at the end of my course and i am completely lost and i do absolutly horrible with algebra

anonymous · Answer

thank you to everyone got it correct :) will probably be back for more help