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Trigonometry 22 Online
OpenStudy (anonymous):

please help with piece wise graph

OpenStudy (anonymous):

http://vvcap.net/db/Ea8WobNvpKnowqaCZesR.htp

OpenStudy (tkhunny):

Seriously, Sal? They're ALL lines! Please pull out your 2-point form for a line and use it over and over and over. Let's see what you get.

OpenStudy (anonymous):

maybe im just that dumb

OpenStudy (anonymous):

please explain

OpenStudy (anonymous):

mx+b?

OpenStudy (tkhunny):

That is the Slope-Intercept Form of a line. You need the 2-Point Form of a Line. Do you have it?

OpenStudy (anonymous):

no :(

OpenStudy (tkhunny):

That's not good at all. Slope-Intercept: y = mx + b Point-Slope: (y-y0) = m(x-x0) Two-Point: (y-y0) = [(y1-y0)/(x1-x0)](x-x0) Given Slope = 5 and y-intercept = 3, we have Slope-Intercept: y = 5x + 3 Given Slope = 4 and point (2,6), we have Point-Slope: (y-6) = 4(x-2) Given Point (3,1) and point (7,5), we have Two-Point: (y-1) = [(5-1)/(7-3)](x-3) Your piecewise definitions require the use of the two-point for. Identify two points on each line segement and you're nearly done.

OpenStudy (anonymous):

\[f(x)=\left\{ x=3 ; 0 \le x \le 3\right\}\]?

OpenStudy (anonymous):

thats for the first one, am i on the right path?

OpenStudy (tkhunny):

You're in the ballpark, but you are pointed the wrong way. Should be y = 4. The next piece contains points (3,4) and (6,1)

OpenStudy (anonymous):

am i going to have 4 set of points? 2 for each line? because i got L1= (0,4) (3,4) L2= (3,4) (6,1)

OpenStudy (tkhunny):

That is correct. Except, just write down the vertical and horizontal ones. (0,4)(3,4) should lead immediately to y = 4

OpenStudy (anonymous):

just because both y1 and y2 are 4s? or do i have to plug them into some equation?

OpenStudy (tkhunny):

You can if you want. Or, you can just notice that those are easier and just write it down. Same thing with equal x-values when you encounter those. (2,3),(2,7) ==> x = 2 Done.

OpenStudy (anonymous):

i give up. im not getting this.

OpenStudy (tkhunny):

Two Points. Put them in the 2-point form. It doesn't have to be harder than that.

OpenStudy (stacey):

I would use the y=mx+b. For the first one there are two pieces: y=4 is the first piece from x=0 to x=3.

OpenStudy (stacey):

For the second piece, you can look at rise over run to find the slope. From the left-hand point (3,4), we go down three and then right three to get to the right-hand point (6,1). That means the slope is 3/3 or 1, so m=1.

OpenStudy (stacey):

So far for y=mx+b, we have y=1x+b or simply y=x+b. Now we can use one of the points to find b. Using (3,4), x=3 and y=4. We subsitute those values into y=x+b. 4=3+b Subtract 3 from both sides and b=4. Now we have m and b to plug into y=mx+b. The equation for our second piece is y=x+4.

OpenStudy (stacey):

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