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Mathematics 19 Online
OpenStudy (anonymous):

Plz help with Algerbra word prob?

OpenStudy (anonymous):

The volume of gas varies directly with temperature and inversely with pressure. Volume is 100m^3 when temperature is 1508 degrees and pressure is 15 lb/cm^2. What is the volume when the temperature is 2508 degrees and the pressure is 20 lb/cm^2?

OpenStudy (anonymous):

if volume varies directly with temp, then when temp goes up, volume goes up, also inversely and pressure goes up volume goes down. so Volume = Temp/Pressure since this would represent as temp goes up volume goes and and the volume decreases and pressure does since a larger denominator gives a smaller number

OpenStudy (anonymous):

also there is a proportionality number so the final equation is V = kT/P where k is some number that makes the problem true. you have given V T and P from the first 3 numbers. so find k, then using the second numbers after temp and pressure change and the k found from before to find the new Volume

OpenStudy (anonymous):

so 100 = k(1508)/15 you can solve for k then V = k(which is found)*2508/20

OpenStudy (anonymous):

So V=124.6?

OpenStudy (anonymous):

yes and the units on it is m^3

OpenStudy (anonymous):

thnx so much then

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