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Mathematics 19 Online
OpenStudy (anonymous):

factor 4y^2-9

OpenStudy (zehanz):

It is of the form a² - b² = (a + b)(a - b). Here: a² = 4y² and b² = 9. So if you can figure out a and b, you can factor it!

OpenStudy (anonymous):

would it be (4y+3)(4y-3) ?

OpenStudy (whpalmer4):

Close, but not quite. 4*4 = 16.

OpenStudy (whpalmer4):

\[a^2 = 4y^2\]Take square root of both sides \[a=\sqrt{4y^2} = ?\]

OpenStudy (anonymous):

oh haha so it would be (2y+3)(2y-3)

OpenStudy (zehanz):

Right!

OpenStudy (whpalmer4):

By the way, learning to recognize difference of squares like this is an important trick in your bag of factoring tricks.

OpenStudy (anonymous):

okay! haha blonde moment! :)

OpenStudy (zehanz):

We all have that once in a while!

OpenStudy (anonymous):

haha this is my 6 th one today :/

OpenStudy (whpalmer4):

And whenever you think you've solved something, or factored it, it's not a bad idea at all to expand it out or plug in the solution and make sure that your answer works!

OpenStudy (zehanz):

You used them up for the whole week already!

OpenStudy (whpalmer4):

Might have to wear a wig for a few days ;-)

OpenStudy (anonymous):

haha thanks guys! and its natural I cant help it. and the wig wouldnt hide anything. honestly ive tried that and it didn't work:(

OpenStudy (zehanz):

Just learn to live with it ;)

OpenStudy (anonymous):

haha I do! I just accept im a natural blonde but at least im not a bimbo!

OpenStudy (zehanz):

Good luck with your maths problems!

OpenStudy (whpalmer4):

I have a friend who is a natural brunette, but she prefers to be blonde, and often pulls it off quite convincingly :-)

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