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Mathematics 9 Online
OpenStudy (anonymous):

See attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

@timo86m

OpenStudy (anonymous):

in the small side solve for the hypatanuse call it H

OpenStudy (anonymous):

I'll rotate it using a photo editor.

OpenStudy (anonymous):

then h/x=8/12

OpenStudy (anonymous):

Oh. Okay.

OpenStudy (anonymous):

nooo need lol find hypotenuse of first small triangle. And lets say it is h then h/x=8/12 solve for x

OpenStudy (anonymous):

pythagorean theorem a^2+b^2=c^2 6^2+8^2=10?

OpenStudy (anonymous):

(sqrt 100 = 10)?

OpenStudy (anonymous):

\[\sqrt{10}\]

OpenStudy (anonymous):

sqrt(6^2+8^2)

OpenStudy (anonymous):

so yes it is 10 :) h=10

OpenStudy (anonymous):

yay! I got it! gracias:D

OpenStudy (anonymous):

sqrt of 100=10 :P

OpenStudy (anonymous):

So now, x/10=8/12?

OpenStudy (anonymous):

so now h/x=8/12 10/x=8/12

OpenStudy (anonymous):

is it ok if i do x/10?

OpenStudy (anonymous):

flip it 123

OpenStudy (anonymous):

[ps we typed almost the same thing;lol]

OpenStudy (anonymous):

Ok 86.:D

OpenStudy (anonymous):

10/x=8/12

OpenStudy (anonymous):

Okay; let me solve.

OpenStudy (anonymous):

15?

OpenStudy (anonymous):

[ft]

OpenStudy (anonymous):

that is simplest way. altho there could be more

OpenStudy (anonymous):

okay. gracias...

OpenStudy (anonymous):

15 ft sounds reasonable.

OpenStudy (anonymous):

okay.

OpenStudy (anonymous):

de nada

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