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@timo86m
in the small side solve for the hypatanuse call it H
I'll rotate it using a photo editor.
then h/x=8/12
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Oh. Okay.
nooo need lol find hypotenuse of first small triangle. And lets say it is h then h/x=8/12 solve for x
pythagorean theorem a^2+b^2=c^2 6^2+8^2=10?
(sqrt 100 = 10)?
\[\sqrt{10}\]
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sqrt(6^2+8^2)
so yes it is 10 :) h=10
yay! I got it! gracias:D
sqrt of 100=10 :P
So now, x/10=8/12?
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so now h/x=8/12 10/x=8/12
is it ok if i do x/10?
flip it 123
[ps we typed almost the same thing;lol]
Ok 86.:D
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10/x=8/12
Okay; let me solve.
15?
[ft]
that is simplest way. altho there could be more
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okay. gracias...
15 ft sounds reasonable.
okay.
de nada
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