Question

d/dx [ln(5x^{3} +4)]

Answer 1

what the chain rule pull out; say if this was just ln(u) ??

Answer 2

okay so it would be...\[\frac{ 5x ^{2} }{ x ^{3} +4}\]

Answer 3

close .. but not quite :)

Answer 4

It should be 3x^{2} at the top

Answer 5

recall\[\frac d{dx}(lnu)=\frac {u'}{u}\]

let u = 5x^3 + 4

u' = 15x^2

Answer 6

you had the right idea tho, and thats good :)

Answer 7

okay, got it! Thanks :)