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Mathematics 19 Online
OpenStudy (anonymous):

What is the equation of the graph below?

OpenStudy (anonymous):

OpenStudy (whpalmer4):

Looks like an inverted parabola with vertex at (-2,2). Do you know how to get the equation from that information?

OpenStudy (anonymous):

Not sure how to

OpenStudy (anonymous):

i know the choices are y = –4(x + 2)2 + 2 y = –4(x – 2)2 + 2 y = 4(x – 2)2 – 2 y = 4(x + 2)2 + 2

OpenStudy (anonymous):

I know it's not C

OpenStudy (whpalmer4):

Well, time to either refresh your memory, or reason it out. Which do you prefer? :-) Reasoning it out is an excellent choice! Okay, we know that this is an inverted parabola, so it must be a - sign in front of the x^2 portion. That eliminates the last two choices, which obviously open upward if you try a few points (x=2,3,4 gives y =-2,2,14 for the 3rd choice, and 66, 102,146 for the 4th) Going back to theory for a moment, if you have a function y = f(x), replacing x with x-2 gives you y = f(x-2). That's the same as shifting the whole graph 2 units to the left — where you used to have some feature of the graph at x, it now appears at x-2, right? Similarly, if we replaced x with x+2, the graph shifts to the right, and something that used to appear at x = 0 would now appear at x=2. Also, there's the shift up / down to account for. Well, that's just adding or subtracting something from the result of f(x). y = f(x)+2 is just going to give us the same graph, shifted up 2 points. y = f(x)-2 gives us the same graph, shifted down two points. Does that make sense? Knowing that, which equation is your choice?

OpenStudy (anonymous):

i think it's B because negative shifts to the left, and the parabola is on the left side of the graph

OpenStudy (whpalmer4):

We can classify all of the choices: A: shifted right by 2, and up by 2, opens down B: shifted left by 2, up by 2, opens down C: shifted left by 2, down by 2, opens up D: shifted right by 2, up by 2, opens up

OpenStudy (whpalmer4):

so B is the correct answer. we could also use vertex form for a parabola: \[y = a(x-h)^2 + k\] where the vertex is at \((h,k)\) \(a\) tells us whether it opens up or down, positive \(a\) opens up, otherwise it opens down.

OpenStudy (whpalmer4):

I hope that helps, I have to leave now.

OpenStudy (anonymous):

thank you very much for the thorough explanations!

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