Question

Find equations of the tangent line and normal line to the curve y=6cosx at the point (π/3,3)

The slope of the tangent line is m1=
The equation of the tangent line is y =
The slope of the normal line is m2=
The equation of the normal line is y=

i have found the derivitive to be y = -6sin(x)

Answer 1

That's the correct derivative. So, plugging in \[\pi\] would give you the slope of the tangent line. Since you have the slope, x-value, and y-value, you can solve for the equation of the line using point-slope form.

The normal line is simply the line perpendicular to that point, being it's the opposite recipricol of the tangent line.