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Why does ln((sinx)^1/2)=1/2ln(sinx)?
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\[\ln((sinx)^{1/2}) = 1/2\ln(sinx)\]
what rule is being used here/when can it be used to pull the exponent out front?
if it matters its a function i'm suposed to differentiate and my book says it would be easier if we simplified the function like that
because it is the definition of logarithm that ln a^b = b ln a
log 1000 = log 10^3 = 3 log 10...this is how log operates
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oh, ok thanks. Didn't know that
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