Greg pulls a rope attached to a sled with a force of 60 N. The rope makes an angle of 60° with the ground, as shown below. What force will move the sled vertically upwards? 42.92 N 51.96 N 30 N 20 N
Do you know how to take x and y components of a force? This should help
I got an error sorry
^ So did I
the picture is just a 60 degree angle
People not using that system won't be able to use links to pages on it.
Well, we can reason it out. If the rope pulls straight up, all of the force is used to pull the sled vertically upwards. We know that there's a sin or a cos in there. Which one? Well, the one that gives us a value of 1 at 90 degrees, which is sin. So, our upward force component must be \(F \sin \theta\). If we plug in our values from this problem, the upward component is \((60N)(\sin 60^\circ ) \approx 51.96 N\). A glance at a diagram confirms that most of the force will be going upward.
thanks that helped a lot
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