Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 65 mi/h. a)Assuming they start at the same point, how much sooner does the faster car arrive at a destination 14 mi away?
b) How far must the faster car travel before it has a 15-min lead on the slower car?

Question

Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 65 mi/h. a)Assuming they start at the same point, how much sooner does the faster car arrive at a destination 14 mi away?
 b) How far must the faster car travel before it has a 15-min lead on the slower car?

anonymous · Answer

a)14miles/55miles per hour minus 14miles/65miles per hour times 60min. per hour equals approx. 2.35 min.

anonymous · Answer

thank you!

anonymous · Answer

b) I think you would multiply the slower speed 55mi/hr by 1.25hr which gives you a distance of 68.75 miles that the faster car would have to drive to be 15 min ahead.