Given that BD ⊥ AC , what is the length of AC ? If necessary, round your answer to two decimal places.
There are two ways to do this: (1) setting up trig ratios, finding the measures of angles, setting up more ratios, and solving for the missing side, then adding the results; and (2) applying Pythagorean's theorem and adding the results. The second method is quicker, but if you're supposed to use trig ratios it's not too difficult.
how would i set it up using Pythagorean's theorem and adding the results??
\[(AD)^2+(7.9)^2=(9.4)^2\\ (DC)^2+(7.9)^2=(23.2)^2\] Then, after finding AD and DC, you have \[AC = AD + DC\]
ok this is what i got for the first one 62.41 = 88.7364
This is what you should be getting for the first one.\[\begin{align*}(AD)^2+(7.9)^2&=(9.4)^2\\ (AD)^2&=(9.4)^2-(7.9)^2\\ (AD)^2&=88.36-62.41\\ (AD)^2&=25.95\\ AD&=\sqrt{25.95}\\ AD&=5.09\end{align*}\]
yes that is waht i got
Okay, now using the same process, find DC, then add it to AD and you get AC.
for the second one i got 21.81 after all the work
i got 26.9 is that correct
Yeah, that's right.
thank you for the help
You're welcome.
can you help me on this other on idk if i have to add all them up or if i do the same here?
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