Question

Solve for x
x^2(x-3)^2-4(x-3)^2=0

Answer 1

\[x^2(x-3)^2-4(x-3)^2=0\]
Factoring out (x - 3)², you have
\[(x-3)^2(x^2-4)=0\]

Answer 2

ok got that\

Answer 3

so then you get (x^2-6x+9)x(x-4) right

Answer 4

No, that doesn't help. What I said tells you that you have either
\[(x-3)^2=0 \text{ or }x^2-4=0.\]
Solving both for x gives you the solutions.

Answer 5

I am stuck for the x(x-4) I got htat far what next

Answer 6

Is it x=3 and x=-4

Answer 7

Can someone please help me

Answer 8

Sorry, was a bit busy.
You're right about the x = 3 as a solution, but not with the other equation.
\[x^2-4=0\\
x^2=4\\
x=\pm\sqrt{4}\\
x=-2,x=2\]

Answer 9

so there are three answers x=-2 and x=2 and x=3

Answer 10

Yes.

Answer 11

thanks