Question

can someone help me evaluate the expression and write the result in the form
a + bi.

7 + 16i/
8i

Answer 1

Is that \[\frac{7+16i}{8i}\]?

If so, a useful tactic is to multiply numerator and denominator by the conjugate of the denominator. If the denominator is \((a+bi)\), the conjugate will be \((a-bi)\). After the dust settles, don't forget that \(i^2=-1\).

Answer 2

@whpalmer4 yes!

Answer 3

@whpalmer4 so how exactly do you solve this

Answer 4

I told you...

\[\frac{7+16i}{8i}*\frac{-8i}{-8i} = \]

Answer 5

\[\frac{7+16i}{8i}*\frac{-8i}{-8i} = \frac{-8i(7+16i)}{-64i^2} = \frac{-8i(7+16i)}{64} \]
Bring it home!