Question

find the exact value of sin^-1(-sqrt3/2) without using a calculator. answer in radians

Answer 1

\[\sin^{-1} (-\sqrt{3}/2)\]
\[-\sin^{-1} (\sqrt{3}/2)\]
\[-\pi/3\]

Answer 2

becuase \[\sin (\pi/3)=\sqrt{3}/2\]

Answer 3

and
\[\sin^{-1} (-x)=-\sin^{-1} (x)\]

Answer 4

thanks

Answer 5

u are welcome...

Answer 6

any other doubts...

Answer 7

yeh one more
can you show tan^-1(11/7)-tan^-1(2/9)=pi/4 without using a calculator?

Answer 8

ya...

Answer 9

apply the formula...
\[\tan^{-1} (x)-\tan^{-1} (y)=\tan^{-1} ((x-y)/(1+xy))\]

Answer 10

x=11/7 and y=2/9

Answer 11

thanks alot

Answer 12

its ok