Question

Find x.

Answer 1

http://roads.advancedacademics.com/contentserver/content/roadssection/279450//geometry_4.3_quiz_15q.gif can someone show me how to do it i forgot its been a while

Answer 2

@blondie16

Answer 3

it's a 30-60-90 triangle

Answer 4

ok

Answer 5

can u help me solve it ?

Answer 6

yeah, it's a special case but if you want you could use trig relationships

Answer 7

so you have the hypotenuse is 2 root 3 and you're looking for the adjacent side which is x

Answer 8

do you remember which trig relationship is adjacent over hypotenuse?

Answer 9

umm not quite sure

Answer 10

dont i devide by sqrt 3 to the hypotnuse?

Answer 11

yeah, that's essentially right, because cos(30) is 1/sqrt3 and cos is adj/hyp.
so you have cos30=x/2 sqrt3 and plugging in for cos(30) you get 1/sqrt3 * 2sqrt3 = x.

so x ends up being 2sqrt3/sqrt3.

Answer 12

it's kind of circular because a lot of people use 30-60-90 triangles to remember cos(30).

Answer 13

ohh ok thx and with the other i forgot wat it was 45- something i for got i multiply by sqrt 2 ?

Answer 14

yeah, the other special one is 45 45 90, which has legs of x and hyp x*sqrt2. But I messed up 30 60 90 sorry

Answer 15

cos 30 is actually sqrt3/2. which means you'd have sqrt3/2*2(sqrt3)=x. so x=3.

Answer 16

so 45 45 90 ix x, x, and x*sqrt2. 30 60 90 the shortest leg is x, the other leg is x*sqrt3, and the hyp is 2x.

Answer 17

sorry for the brain fart

Answer 18

lolo thx