Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Match the graphs of the functions on the left with the graphs of their derivatives on the right.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (zehanz):

Do you know what the derivative of a 2nd degree function is?

OpenStudy (anonymous):

no

OpenStudy (zehanz):

You know the following I guess: If f is decreasing, then f' is negative (and vice versa). If f is increasing, then f' is positive ( and vv).

OpenStudy (anonymous):

yes

OpenStudy (zehanz):

No look at the first graph on the left. To the left of the y-axis, it is decreasing, to the right it is increasing.

OpenStudy (anonymous):

yes it does

OpenStudy (zehanz):

This means, for f' you are looking for a function that is negative on the left side of the y-axis and positive on the right.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so it will be #2 in the second attachment?

OpenStudy (zehanz):

I can see it on one of your drawings on the right! Do you?

OpenStudy (anonymous):

Yes it will be number 2 ?

OpenStudy (anonymous):

so to will have letter A

OpenStudy (zehanz):

No, I've got C

OpenStudy (anonymous):

but you can't match a with c , it says to match the left with the right so it has to be a letter with a number

OpenStudy (zehanz):

I mean this (see image) The parabola on the left (2nd degree function) has the straight line on the right as it's derivative.

OpenStudy (anonymous):

so number one will be 1 with letter c?

OpenStudy (anonymous):

I meant number 2 sorry

OpenStudy (anonymous):

so 2C ?

OpenStudy (zehanz):

Yes

OpenStudy (anonymous):

okay

OpenStudy (zehanz):

Now try #2. See what it does: increasing, decreasing, increasing. So you're looking for a graph that is +, then -, then +.

OpenStudy (anonymous):

i thought we already did number 2

OpenStudy (anonymous):

?

zepdrix (zepdrix):

He was telling you number #1 is C. There musta been some confusion there c:

OpenStudy (anonymous):

ohhh okay lol sorry

OpenStudy (anonymous):

so number 2 will be f?

OpenStudy (zehanz):

@zepdrix: thx

OpenStudy (zehanz):

Yes!

OpenStudy (anonymous):

okay :)

OpenStudy (zehanz):

I think you got it!

OpenStudy (anonymous):

number 3 looks funny

zepdrix (zepdrix):

I think #2 is `e` actually :o hmm

OpenStudy (zehanz):

It is down, up, down, up, so look for -,+,-,+

OpenStudy (anonymous):

okay so number 3 will be A ?

OpenStudy (zehanz):

@zepdrix : you're right, I'm having trouble looking at three different pictures, @onegirl: sorry ;)

OpenStudy (anonymous):

okay thanks for the correction zep

OpenStudy (anonymous):

so 3A ?

OpenStudy (zehanz):

Yes, 3A

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so number 4 will be D?

OpenStudy (zehanz):

Right again! Always decreasing, so looking for a derivative that is always negative...

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so i'm guessing number 5 will be 5B?

OpenStudy (anonymous):

?

OpenStudy (zehanz):

You guessed wrong... Look at graph #5 and compare with #3

OpenStudy (zehanz):

It behaves in the same way: dec, inc, dec, inc, so -,+,-,+

OpenStudy (anonymous):

ok so it will be 5f

OpenStudy (zehanz):

Oops, look something went wrong with my last response. Because 5 and 3 behave in the same way, you have to choose the same derivative: 5A

OpenStudy (anonymous):

ohh ok

OpenStudy (anonymous):

so letter A goes to two graphs? okay

OpenStudy (zehanz):

That's the mean part of the question ;)

OpenStudy (anonymous):

okay so how about the last one number 6?

OpenStudy (zehanz):

It goes down, then up, then down, so for f' we have: neg, pos, neg

OpenStudy (anonymous):

so it will be 6B

OpenStudy (zehanz):

No, that goes a lot more from - to + etc.

OpenStudy (zehanz):

(it is really simple)

OpenStudy (anonymous):

ohh so it will f since it does go negative pos then neg

OpenStudy (zehanz):

Yes, it's 6F. I must admit this kind of question can be confusing, because you constantly have to switch from increasing , decreasing to +, -.

OpenStudy (anonymous):

okay well thanks for your help

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!